Electric Field Calculator

V/m

A fast electric field estimate is valuable only when the setup is clear. Many E&M relationships are simple proportionalities or inverse powers, making a one-input sensitivity check an effective way to catch unit mistakes. The sections below show exactly what this page calculates, how to enter the data, and where the simplified model stops.

What this calculator does

The calculator isolates the relationship between Relative permittivity (ϵᵣ), Charge (Q), Distance (r) and electric field. That makes it useful for testing how one input changes the answer without mixing in unrelated assumptions.

How to use it

Fill in Relative permittivity (ϵᵣ), Charge (Q), Distance (r), Electric field (E) exactly as defined on the page. Set Electric field of a… to match the solve path you want. After calculating, change one influential input slightly and confirm that the result moves in the direction predicted by the equation; this is a quick unit and setup check.

How the calculation works

For a point charge in a medium, E = q/(4πε0εr r²). The sign follows the charge; the supporting magnitude removes that sign for field strength.

Example

For a simple vacuum check, enter q = 1 nC, r = 0.1 m, and relative permittivity 1. The point-charge equation gives about 899 V/m. Doubling the distance to 0.2 m should reduce the magnitude to roughly one quarter.

How to interpret the result

Use the electric field as the result of the stated electromagnetic relationship. Check whether the output is linear, inverse, inverse-square, or logarithmic before judging how a change in one input should affect it.

Limitations and notes

Real electrical and magnetic systems can add parasitics, finite geometry, temperature dependence, nonlinear materials, frequency-dependent losses, tolerances, and measurement uncertainty beyond the ideal relationship shown here. Before carrying the number into a design or report, confirm Relative permittivity (ϵᵣ), Charge (Q), the unit system, and the model assumptions. Extra decimal places do not compensate for an input that represents the wrong physical quantity.

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