Thermal Stress Calculator
Report a calculator issue
Choose the problem type and tell us what went wrong.
When you need a quick thermal stress check, the best result is one you can explain, not just copy. Stress, strain, stiffness, and section properties are tightly tied to geometry, so a correct formula can still give the wrong engineering answer when the wrong dimension is entered. The calculator below uses a narrow equation set and shows the output in a form that is easy to sanity-check.
What this calculator does
The Thermal Stress Calculator is a focused solver for thermal stress using Thermal expansion coefficient (α), Young’s modulus (Eₘ), Initial temperature (Tᵢ). Its job is to make the active equation and the quantities feeding it easy to inspect rather than model every possible real-world effect.
How to use it
Begin with Thermal expansion coefficient (α), Young’s modulus (Eₘ), Initial temperature (Tᵢ), Final temperature (T𝒇). Do not strip the units from those values when copying them from a datasheet or measurement. Once calculated, vary the most influential input slightly and confirm that the response agrees with the equation before using the number elsewhere.
How the calculation works
The page uses the fully restrained linear-thermal model σ = EαΔT, with ΔT = Tf−Ti. Thermal strain is αΔT. This assumes the expansion is prevented rather than freely accommodated.
Example
Using the default example on the page (Thermal expansion coefficient (α) = 1.2e-05 1/K; Young’s modulus (Eₘ) = 200 GPa; Initial temperature (Tᵢ) = 20 °C; Final temperature (T𝒇) = 80 °C), the calculator returns thermal stress of 144,000,000 Pa. Try increasing one input while holding the others fixed; the response should match the dependence shown in the formula above.
How to interpret the result
The thermal stress describes the modeled specimen or section, not every possible failure mode. A useful check is whether increasing a numerator term raises the answer and increasing a denominator term lowers it as the equation predicts.
Limitations and notes
The formula assumes complete restraint and linear elastic response. If the component can expand, if the temperature field is nonuniform, or if yielding/creep/contact compliance occurs, actual thermal stress can be much lower or spatially varying. The material selector does not currently replace E or α.
Was this article helpful?
Your answer helps us improve the clarity and usefulness of our health content.